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12x^2-76x-160=0
a = 12; b = -76; c = -160;
Δ = b2-4ac
Δ = -762-4·12·(-160)
Δ = 13456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{13456}=116$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-76)-116}{2*12}=\frac{-40}{24} =-1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-76)+116}{2*12}=\frac{192}{24} =8 $
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